Answer:
![\boxed{\sf Acceleration \ of \ the \ car = -5 \ m/s^2}](https://img.qammunity.org/2021/formulas/physics/high-school/hl4ilxpgbv1ig0dv0r0rvow57r302yfzgw.png)
Given:
Initial speed (u) = 30 m/s
Final speed (v) = 20 m/s
Time taken (t) = 2s
To Find:
Acceleration (a) of the car
Step-by-step explanation:
From equation of motion we have:
![\boxed{ \bold{v = u + at}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/ednjptx8nanvxuk6r04j9hx7sl2p9vdw67.png)
By substituting value of v, u & t in the equation we get:
![\sf \implies 20 = 30 + a(2) \\ \\ \sf \implies 2a + 30 = 20 \\ \\ \sf \implies 2a = 20 - 30 \\ \\ \sf \implies 2a = - 10 \\ \\ \sf \implies a = - (10)/(2) \\ \\ \sf \implies a = - 5 \: m {s}^( - 2)](https://img.qammunity.org/2021/formulas/physics/high-school/85rnx67p60q0o80ogwtz5dflli4ff7qlwm.png)
![\therefore](https://img.qammunity.org/2021/formulas/mathematics/high-school/zvcp35s3bq26ivrtwrqv1wpy3rbhge44qb.png)
Acceleration (a) of the car = -5 m/s²