Question

Which of the following ordered pairs is not a solution of the system of inequalities? y > x2 – 4x – 5 y < –x2 – 5x + 6 Question 62 options: A) (1, 7) B) (1, –7) C) (1, –5) D) (–1, 6)

Answer 1

Its Not (1,7) i took the test and missed it

Explanation:

Answer 2

a) (x, y) = (1, 7)

Explanation:

Let be the following system of inequalties:

`y > x^(2)-4\cdot x -5`

`y < -x^(2)-5\cdot x +6`

We can find the right option by evaluating each option in the system of inequalities:

a) (x, y) = (1, 7)

`7 > 1^(2)-4\cdot (1) -5`

`7 < -1^(2)-5\cdot (1) +6`

Then,

`7>-8` (TRUE)

`7<0` (FALSE)

(1, 7) is not a solution of the system of inequalities.

b) (x, y) = (1, -7)

`-7 > 1^(2)-4\cdot (1) -5`

`-7 < -1^(2)-5\cdot (1) +6`

Then,

`-7 > - 8` (TRUE)

`-7< 0` (TRUE)

(1, -7) is a solution of the system of inequalities.

c) (x, y) = (1, -5)

`-5 > 1^(2)-4\cdot (1) -5`

`-5 < -1^(2)-5\cdot (1) +6`

Then,

`-5 > - 8` (TRUE)

`-5< 0` (TRUE)

(1, -5) is a solution of the system of inequalities.

d) (x, y) = (-1, 6)

`6 > (-1)^(2)-4\cdot (-1) -5`

`6 <(-1)^(2)-5\cdot (-1)+6`

Then,

`6>0` (TRUE)

`6 < 12` (TRUE)

(-1, 6) is a solution of the system of inequalties.

Therefore, we conclude that correct answer is A.