Question

11. Point F is on segment EG. If FG = (27x - 50)° and EF = (3x - 2)° and EG = 38,

then find FG. *

Answer 1

Explanation:

27x -50 + 3x - 2 = 38

30x - 52 = 38

30x = 90

x = 3

27(3) - 50 = 81 - 50 = 31 = FG