Final answer:
The frictional force exerted on a student depends on the coefficient of friction and the normal force. It can either prevent slipping or provide the necessary centripetal force for circular motion.
Step-by-step explanation:
The frictional force exerted on a student by a rotating table depends on the coefficient of friction between the student and the table. If the coefficient of friction is large enough, the student will not slip and the frictional force will equal the product of the coefficient of friction and the normal force.
For example, if the coefficient of friction is 0.5 and the normal force is 100 N, then the frictional force will be 0.5 * 100 = 50 N.
However, if the coefficient of friction is not large enough to prevent slipping, the frictional force will be equal to the force required to keep the student in circular motion. This force is called the centripetal force and is provided by the normal force.