Question

H^2 + 11h +18. The factored expression is

Answer 1

`\boxed{ \bold{ \huge{ \boxed{ \sf{(h + 9)(h + 2)}}}}}`

Explanation:

`\sf{ {h}^(2) + 11h + 18}`

Here, we have to find out two numbers that adds to 11 and multiplies to 18

`\dashrightarrow{ \sf{ {h}^(2) + (9 + 2)h + 18}}`

Distribute h through the parentheses

`\dashrightarrow{ \sf{ {h}^(2) + 9h + 2h + 18}}`

Take h as common. Similarly, take 2 as common

`\dashrightarrow{ \sf{h(h + 9) + 2(h + 9)}}`

`\dashrightarrow{ \sf{(h + 9)(h + 2)}}`

Hope I helped!

Best regards! :F

Answer 2

(h+9)⋅(h+2)

Explanation:

1.1 Factoring h2+11h+18

The first term is, h2 its coefficient is 1 .

The middle term is, +11h its coefficient is 11 .

The last term, "the constant", is +18

Step-1 : Multiply the coefficient of the first term by the constant 1 • 18 = 18

Step-2 : Find two factors of 18 whose sum equals the coefficient of the middle term, which is 11 . -18 + -1 = -19

-9 + -2 = -11

-6 + -3 = -9

-3 + -6 = -9

-2 + -9 = -11

-1 + -18 = -19

1 + 18 = 19

2 + 9 = 11 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 2 and 9

h2 + 2h + 9h + 18

Step-4 : Add up the first 2 terms, pulling out like factors :

h • (h+2)

Add up the last 2 terms, pulling out common factors :

9 • (h+2)

Step-5 : Add up the four terms of step 4 :

(h+9) • (h+2)

Which is the desired factorization