What is the solution of the equation? 3(y-5)+2=5

Question

asked Sep 28, 2021 59.5k views

1 Answer

Mon Io · Answer 1 · 2021-10-02T10:22:37+0000

Answer:

Y=- 6

3(y-5)+2=5

multiply

3y-15+2=5

add

3y-13=5

add pos 13 to the neg 13 to

cancel it out and add +13 to 5

3y=18

divide -3 to pos 3 and 18 to cancel it out

y= -6