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What is the temperature of 2.60 mol of gas at a pressure of 102.63 atm and a volume of 341 mL

User Vityavv
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1 Answer

7 votes

Answer:

164.04 K

Step-by-step explanation:

PV = n RT R = gas constant = .082057 L-atm/(mol-K)

T will be in K

102.63 (.341) = 2.60 * .082057 * K

K = 164.04 K

User Snehal
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