Question

a cart rolls down a track. it starts from rest and attains a speed of 2.7 m/s in 3 s, what is the acceleration and distance traveled?

Answer 1

Acceleration and the distance traveled are 0.9 m/s² and 4.05 m

Step-by-step explanation:

Given that,

Initail speed, u = 0

Final speed, v = 2.7 m/s

Time, t = 3 s

To find,

The acceleration and distance traveled.

Solution,

Acceleration is change in speed per unit time

`a=(v-u)/(t)\\\\a=(2.7-0)/(3)\\\\a=0.9\ m/s^2`

Let s is the distance,

`d=ut+(1)/(2)at^2\\\\\because u=0\\\\d=0+(1)/(2)* 0.9* 3^2\\\\d=4.05\ m`

So, acceleration and the distance traveled are 0.9 m/s² and 4.05 m