Question

Write the sum without sigma notation. Then evaluate the sum.∑2k=1 40k/k+3Choose the correct answer belowA. (40⋅1/1+3)+(40⋅2/2+3) B. 40k/2+3 C. 40⋅2/2+3 D. (40⋅1.1+3)+(40⋅2/2+3)+(40⋅3/3+3)

Answer 1

A. (40⋅1/1+3)+(40⋅2/2+3)

Explanation:

Given that:

`\sum \limits ^2 _(k=1) (40 \ k )/(k + 3)`

which can be expressed as:

=
`(40* 1 )/(1 + 3) + (40* 2 )/(2 + 3)`

=
`(40 )/(4) + (80 )/(5)`

=
`10+ 16`

= 26

∴

`\sum \limits ^2 _(k=1) (40 \ k )/(k + 3) = 26`