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find an equation of the line passing through the point (5 4) and parallel to the line whose equation is y= 2x-6

1 Answer

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Answer:


y = 2x - 6

Explanation:

Given

Equation:
y = 2x - 6

Required

Determine the equation of Point: (5,4)

First, we need to determine the slope of
y = 2x - 6

The general form of an equation is
y = mx + b

Where m represents the slope;

Hence;
m =2

Since the equation and the point are parallel. then they have the same slope (m).


m = 2

Next, is to determine the equation of the point, using the following formula:


m = (y - y_1)/(x - x_1)

Where


(x_1,y_1) = (5,4)

So, the equation becomes


2 = (y - 4)/(x - 5)

Cross Multiply


y - 4 = 2(x - 5)

Open Bracket


y - 4 = 2x - 10

Make y the subject of formula


y = 2x - 10 + 4


y = 2x - 6

Hence, the equation is
y = 2x - 6

User Jfklein
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