Question

A snowboarder on a slope starts from rest and reaches a speed of 8.9 m/s after 9.5 s.

How far does the snowboarder travel in this time?

Answer 1

Step-by-step explanation:

Given that,

Initial speed, u = 0

Final speed, v = 8.9 m/s

Time, t = 9.5 s

Let a is the acceleration of the snowboarder. It can be calculated as follows :

`a=(v-u)/(t)\\\\a=(8.9-0)/(9.5)\\\\a=0.936\ m/s^2`

The distance traveled by the snowboarder in this time is calculated using third equation of motion as follows :

`v^2=u^2=2as\\\\s=(v^2)/(2a)\\\\s=((8.9)^2)/(2* 0.936)\\\\s=42.31\ m`

So, 42.31 m of distance is traveled by snowboarder in this time.