Question

A car slows down uniformly from a speed of 22 m/s to rest in 4.0 seconds. How far did it travel in that time

Answer 1

`\boxed{\sf Distance \ travelled = 44 \ m}`

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Step-by-step explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

`\boxed{ \bold{s = ((v + u)/(2) )t}}`

By substituting value of v, u & t in the equation we get:

`\sf \implies s = ( (0 + 22)/(2) ) * 4 \\ \\ \sf \implies s = (22)/(2) * 4 \\ \\ \sf \implies s = 11 * 4 \\ \\ \sf \implies s = 44 \: m`

`\therefore`

Distance travelled by car (s) = 44 m