Question

Hellp me solve this thanks

Answer 1

c. 10 cm

Explanation:

The parallel sides of trapizium are the bases so

base 1(B1) =9cm , base(B2)= 12cm

`area(a) = 105 {cm}^(2)`

the perpendicular distance means the height so lets find the height

area of trapizium= B1 + B2 × h

2

`{105cm}^(2)(the \: given \: area) = (9cm(the \: given \: base) + 12cm(the \: given \: base))/(2) * h`

`{105cm}^(2) = (21cm)/(2) * h`

now we crisscross

`{105cm}^(2) * 2 = 21cm * h`

`{210cm}^(2) = 21cm * h`

`\frac{ {210cm}^(2) }{21cm} = (21cm \: )/(21cm) * h`

h = 10 cm

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