Question

Write the electron configuration for the following elements. (1) Neon, (2) Zinc, (3) Tungsten, (4) Magnesium

Answer 1

Step-by-step explanation:

Hey there!!

We generally use s,p,d,f formula.

So, let's do with it.

1.Neon

Atomic no. = 10

So, Its electronic configuration is;

`= 1 {s}^(2) .2 {s}^(2) 2 {p}^(6)`

2.Zinc.

Atomic no. = 30

So, it's electronic configuration is;

`= 1 {s}^(2) 2 {s}^(2) 2 {p}^(6) 3 {s}^(2) 3 {p}^(6) 4 {s}^(2) 3 {d}^(10)`

3. Tungsten.

Atomic no. = 74.

So, it's electronic configuration is;

`= 1 {s}^(2) 2 {s}^(2) 2 {p}^(6) 3 {s}^(2) 3 {p}^(6) 4 {s}^(2) 3 {d}^(10)4 {p}^(6) 5 {s}^(2) 4 {d}^(10) 5 {p}^(6) 6 {s}^(2) 4 {f}^(14) 5 {d}^(4)`

4. Magnesium.

Atomic no. = 12

So, the electronic configuration is ;

`= 1 {s}^(2) 2 {s}^(2) 2 {p}^(6)3 {s}^(2)`

Hope it helps...