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If x+y=3, x²+y²=5 then find the value of xy

User Euan
by
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1 Answer

4 votes

Answer:


\huge\boxed{xy = 2}

Explanation:

=>
\sf (x+y)^2 = x^2 + y^2 + 2xy

Given that
\sf x + y = 3 , x^2 + y^2 = 5

=>
\sf (3)^2 = 5 + 2xy

=>
9 = 5 + 2xy

=>
9-5 = 2xy

=>
4 = 2xy

Dividing both sides by 2

=> 2 = xy

OR

=> xy = 2

User Lie
by
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