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The product of two whole number is 462 and their sum is 43. What are the two numbers?

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7 votes

Answer:

21 and 22

Explanation:

Let the two whole numbers be a and b.

Their product is 462. Hence, we can write that:


ab=462

Likewise, because their sum is 42:


a+b=43

This yields a system of equations:


\displaystyle \begin{cases} ab = 462 \\ a + b = 43 \end{cases}

We can solve the system using substitution.

Isolating one variable in the second equation yields:


a=43-b

From substitution:


(43-b)(b)=462

Distributing yields:


-b^2+43b=462

Solve for b by factoring:


\displaystyle \begin{aligned} b^2 - 43d & = -462 \\ \\ b^2 - 43d + 462 & = 0 \\ \\ (b-21)(b-22) &= 0 \\ \\ b = 21 \text{ or } b & = 22 \end{aligned}

Solve for a:


\displaystyle \begin{aligned} a& =43-(21) & \text{ or } a& =43-(22) \\ a&=22&\text{ or } a&=21\end{aligned}

In conclusion, the two whole numbers are 21 and 22.

User HelmiB
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