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Given directed line segment CD, if point E divides CD three-fourths of the way

from C to D. find the coordinates of E. Round to the nearest tenth.

User Sladomic
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1 Answer

2 votes

Answer:

E(-2, -1.5)

Step-by-step explanation:

From the diagram attached, the coordinates of point C and D are at C(1, 6) and D(-3,-4)

If a line segment AB with coordinates at
(x_1,y_1)\ and\ (x_2,y_2) is divided by a point O(x, y) in the ratio n:m, the coordinates of point O is given by the formula:


x=(n)/(n+m)(x_2-x_1)+x_1 \\\\y=(n)/(n+m)(y_2-y_1)+y_1

C(1, 6) and D(-3,-4) are divided three fourths (in ratio 3:1) by point E. Let us assume E is at (x,y), hence the coordinate of point L is given as:


x=(n)/(n+m)(x_2-x_1)+x_1=(3)/(4)(-3-1)+1=(3)/(4)(-4)+1=-2 \\\\y=(n)/(n+m)(y_2-y_1)+y_1=(3)/(4)(-4-6)+6=(3)/(4) (-10)+6=-1.5

Point E is at (-2, -1.5)

Given directed line segment CD, if point E divides CD three-fourths of the way from-example-1
User Torez
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