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An estate agent has three houses for sale. The prices of the houses were
in the ratio 6:4:3 and the cheapest house was priced at $240 000. What
were the prices of the other two houses? (SHOW WORKING)​

User Ojmeny
by
5.2k points

1 Answer

6 votes

Answer:

Explanation:

sum of ratio=6+4+3=13

let the total price of houses=x

then


(3)/(13) x=240,000\\x=240,000 * (13)/(3) =1,040,000\\price of first house=1,040,000 * (6)/(13) =480,000\\price~of~second~house=1,040,000 * (4)/(13)=320,000

User Chuck W
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