Question

1. Isotonic saline requires a concentration of 0.85% NaCl. How much solid NaCl must be weighed out on the balance to prepare a bottle full containing 3500 ml?

Answer 1

Given :

Concentration of NaCl ,
`c=0.85 \%` .

To Find :

Th amount of solid NaCl must be weighed out on the balance to prepare a bottle full containing 3500 ml .

Solution :

Concentration of NaCl is 0.85 % .

It means , 0.85 gm of NaCl in 100 ml of water .

So , amount of solid NaCl required to prepare 3500 ml solution is :

`x=(3500* 0.85)/(100)\ gm\\\\x=29.75\ gm`

Therefore , amount of solid NaCl required is 29.75 gm .

Hence , this is the required solution .