Question

A number cube is tossed 8 times. What is the probability that the cube never lands on 3?

O A 6.0%
e.
B. 10.4%
O C. 16.7%
e
D. 23.3%

Answer 1

`Probability = 23.3\%`

Explanation:

Given

Number cube

Toss = 8

Required

Probability of not landing on 3

First we need to get the probability of landing on 3 in a single toss;

For a number cube;

`n(3) = 1` and
`n(Total) = 6`

So; the probability is

`P(3) = (1)/(6)`

First we need to get the probability of not landing on 3 in a single toss;

Opposite probability = 1;

So:

`P(3) + P(3') = 1`

Make P(3') the subject of formula:

`P(3') = 1 - P(3)`

`P(3') = 1 - (1)/(6)`

`P(3') = (5)/(6)`

In 8 toss, the required probability is

`Probability = (P(3'))^8`

This gives

`Probability = ((5)/(6))^8`

`Probability = (390625)/(1679616)`

`Probability = 0.23256803936`

Convert to percentage

`Probability = 23.256803936\%`

Approximate to 1 decimal place:

`Probability = 23.3\%`