Question

A body of mass 10kg at rest is subjected force of 16N. Find the kinetic energy at end of 20s.​

Answer 1

`QUESTION:`

a body of mass 10kg at rest is subjected force of 16N. Find the kinetic energy at end of 20s.

`SOLUTION:`

`Given`
`that:`

• Mass = 10kg
• Initial Velocity (u) = 0
• Force = 16 N
• Time = 20 seconds

» Finding for the acceleration:

`a=F/m`

`a=16N/10kg`

`a=1.6/s^2`

» Then velocity after 20 seconds will be:

`v=u+at`

`v=0+1.6m/s^2(20s)`

`v=32/s^`

» Now , Finding for the kinetic energy:

`K=1*2mv^2`

`K=1/2(10)(32)^2`

`K=5(1024)`

`K=5120`
`J`

`ANSWER:`

• The kinetic energy aquired by the body is 5,120 Joules

Answer 2

===================================

`\large \sf \underline{Problem:}`

• A body of mass 10kg at rest is subjected force of 16N. Find the kinetic energy at end of 20s.

===================================

`\large \sf \underline{Answer:}`

`\huge \qquad \quad \sf{5,120 \: Joules}`

===================================

`\large \sf \underline{Solution:}`

Firstly, find the acceleration:

• 
  `\sf{A = F/m}`
• 
  `\sf{A = 16N/10kg}`
• 
  `\sf \pmb{A = 1.6m/s^2}`

Secondly, the velocity after 20 seconds will be:

• 
  `\sf{V =u+at}`
• 
  `\sf{V =0+1.6m/s^2(20s)}`
• 
  `\sf \pmb{V =32m/s}`

Lastly, find the kinetic energy:

• 
  `\sf{K=1/2mv^2}`
• 
  `\sf{K=1/2(10)(32)^2}`
• 
  `\sf{K=5(1024)}`
• 
  `\sf{\underline{\underline{\pmb{K=5120\:J}}}}`

Hence, the kinetic energy at the end is 5,120 Joules.

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