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A dragon accidently swallows a sip of water, H2O(1). When the sip of water enters the dragons stomach which is at 125C (considerably hotter than our human stomachs) it instantly becomes and fills the volume of the dragons stomach which is 112L. How many moles of water did the dragon swallow? Since the dragon is on the ground when he drinks the water the pressure inside stomach is 1.0atm.

User Gbrener
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2 Answers

10 votes
10 votes
  • P=1atm
  • V=112L
  • T=125°C=398K

Now

Ideal gas equation


\\ \rm\Rrightarrow PV=nRT


\\ \rm\Rrightarrow 112=n(8.314)(398)


\\ \rm\Rrightarrow n=0.033mol

User Thesimm
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3.0k points
18 votes
18 votes

Answer:


0.03384\ mol

Step-by-step explanation:

Step 1: Determine important information

Ideal gas law →
PV=nRT

At the end of the problem statement we can see that the pressure is
1.0\ atm. V is the volume which is given as
112\ L. n is the amount of substance which is what we are trying to find. R is the ideal gas constant is the same for every problem which is
8.3145\ J * mol^(-1)*K^(-1). Finally, T is the temperature which is given as
125\ C but we have to convert to kelvins which we get
398\ K.

Step 2: Plug in the information and solve


PV=nRT


(1.0\ atm)*(112\ L) = n*(8.3145\ J * mol^(-1)*K^(-1))*(398\ K)


112=n*(3,309.171)


(112)/((3,309.171))=(n*(3,309.171))/((3,309.171))


0.03385\ mol = n

Answer:
0.03384\ mol

User AhmedZah
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2.2k points