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If for two non-zero vectors a,b : ∣a+b∣=∣a−b∣ then angle between them is:______a. 0b. 45c. 60d. 90

1 Answer

3 votes

Answer:


90^\circ

Explanation:

Given two non zero vectors,
\vec a, \vec b.

Let the angle between the two vectors =
\theta

Given that:


|\vec a+\vec b|=|\vec a-\vec b|

Let us have a look at the formula for magnitude of addition of two vectors:


|\vec x+\vec y|=√(x^2+y^2+2xycos\theta)

Where
\theta is the angle between the two vectors.

formula for magnitude of subtraction of two vectors:


|\vec x-\vec y|=√(x^2+y^2-2xycos\theta)

As per the given condition:


√(a^2+b^2+2abcos\theta)=√(a^2+b^2-2abcos\theta)

Squaring both sides:


a^2+b^2+2abcos\theta=a^2+b^2-2abcos\theta\\\Rightarrow 2abcos\theta=-2abcos\theta\\\Rightarrow cos\theta = -cos\theta\\\Rightarrow 2cos\theta = 0\\\Rightarrow cos\theta = 0\\\Rightarrow \theta = 90^\circ

So, the angle between the two vectors is:
90^\circ

User Hallelujah
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