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1 vote

- 3(9x + 20) \geqslant 15x - 20
could you please help me?​

User Lizhen Hu
by
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1 Answer

5 votes

Answer:


x\le \:-(20)/(21)

Explanation:


-3\left(9x+20\right)\ge \:15x-20\\\\\mathrm{Expand\:}-3\left(9x+20\right):\quad -27x-60\\-27x-60\ge \:15x-20\\\\\mathrm{Add\:}60\mathrm{\:to\:both\:sides}\\-27x-60+60\ge \:15x-20+60\\\\\mathrm{Simplify}\\-27x\ge \:15x+40\\\\\mathrm{Subtract\:}15x\mathrm{\:from\:both\:sides}\\-27x-15x\ge \:15x+40-15x\\\\\mathrm{Simplify}\\-42x\ge \:40\\\\\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}\\\left(-42x\right)\left(-1\right)\le \:40\left(-1\right)


Simplify\\42x\le \:-40\\\\\mathrm{Divide\:both\:sides\:by\:}42\\(42x)/(42)\le (-40)/(42)\\\\Simplify\\x\le \:-(20)/(21)

User David Ansermot
by
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