Question

A computer has 38 address lines. How many locations in Mega bytes can it address?

Answer 1

The computer can address 34359,738368 megabytes

Step-by-step explanation:

Given

Address Lines (n) = 38

Required

Determine the number of location it can address

Number of addressable locations (N) in bits is calculated as thus

`N = 2^n.`

Substitute 38 for n

`N = 2^(38)`

`N = 274877906944\ bits`

Next; is to convert from bits to megabytes

Start by converting to bytes

1 bit = 0.125 bytes;

So;

`N = 274877906944 * 0.125\ bytes`

`N = 34359738368\ bytes`

Convert from byte to megabyte

`1\ byte = 10^(-6)\ megabyte`

So;

`N = 34359738368\ * 10^(-6)\ MB`

`N = 34359,738368\ MB`

Hence, the computer can address 34359,738368 megabytes