Question

A plastic wire is wind on a wheel on a radius 3 cm. The whole system is initially at rest. A force is applied on the plastic wire and the wire unwinds from the wheel from its axis of rotation. The wheel is given an angular acceleration of 92.00 rad/s2 for:______.

Answer 1

The torque of the wheel is 0.92 N-m.

Step-by-step explanation:

Given that,

Radius of wire = 3 cm

Angular acceleration = 92.00 rad/s²

Suppose, Mass of wheel is 4 kg and radius is 5 cm. find the torque of the wheel.

We need to calculate the torque of the wheel

Using formula of torque

`\tau=I\alpha`

`\tau=MR^2*\alpha`

Where, M = mass of wheel

R = radius of wheel

`\alpha` = angular acceleration

Put the value into the formula

`\tau=4*(5*10^(-2))^2*92`

`\tau=0.92\ N-m`

Hence, The torque of the wheel is 0.92 N-m.