Question

For the following, identify the most likely value for x.a. BHx b. CHx c. NHx d. CH2Clx

Answer 1

Given :

a.
`BH_x` b.
`CH_x` c.
`NH_x` d.
`CH_2Cl_x` .

To Find :

Find the most likely vale of x for each one .

Solution :

a .
`BH_x`

Because boron have valency of 3 .

So , x = 3 .

b .
`CH_x`

Valency of carbon is 4 .

x = 4 .

c .
`NH_x`

Valency of nitrogen is 3 .

Therefore , x = 3 .

d .
`CH_2Cl_x`

Now ,we know valency of carbon is 4 and hydrogen is 1 .

Also , two hydrogen are already there .

So , only 2 electrons left to share .

Since , chlorine have valency of 1 .

Therefore , only 2 electrons of chlorine can connect .

x = 2 .

Hence , this is the required solution .