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The stock solution is 100 μM the protocol calls for 10 mL solution of 80, 60, 40 and 20 μM. Compute the table.Target Concentration(μM) Volume of stock(mL) Volume of water(mL)20406080

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Answer:

See the answer below

Step-by-step explanation:

Using the dilution equation:

m1v1 = m2v2

m1 =100 μM, v1 = ?, v2 = 10 mL

In order to prepare 80 μM, then m2 = 80 μM

v1 =
(80*10)/(100) = 8 mL

In order to prepare 60 μM

v1 =
(60*10)/(100) = 6 mL

In order to prepare 40 μM

v1 =
(40*10)/(100) = 4 mL

In order to prepare 20 μM

v1 =
(20*10)/(100) = 2 mL

Since the final solution has to be up to the 10 mL mark, the complete table would be:

Target Concentration(μM) Volume of stock(mL) Volume of water(mL)

20 2 8

40 4 6

60 6 4

80 8 2

User Marc Witteveen
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