Question

Write an equation for a polynomial with all the following features a. The degree is 5 b. The polynomial has 4 terms c. The graph of the polynomial crosses the vertical axis at y=12

Answer 1

f(x) = ax^5 + bx^3 + cx^2 + 12.

Explanation:

the degree is 5 so we will have a term like:

ax^5

it crosses the vertical axis at y = 12 so we will have a constant term equal to 12

the polynomial has 4 terms, and we already have two so we can make up two more but the exponent must be between 1 and 4

f(x) = ax^5 + bx^3 + cx^2 + 12.

it has 4 terms, f(0) = 12, then it intersects the y-axis at y = 12, and the maximum exponent is 5, then the degree of f(x) is 5