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A ball with a mass of 3.7 kg is thrown downward with an initial velocity of 8 m/s from a high building. How fast will it be moving after 3 seconds?

User AmirX
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1 Answer

6 votes

Answer:

v=37.4 m/s

Step-by-step explanation:

It is given that,

Mass of a ball, m = 3.7 kg

Initial velocity of the ball is u = 8 m/s

We need to find its velocity after 3 seconds. It is moving downwards. The equation of motion is this case is

v=u+gt


v=8+9.8* 3\\\\v=37.4\ m/s

So, the velocity of the ball after 3 seconds is 37.4 m/s.

User Heneryville
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