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The hypotenuse of a right triangle is 10 inches long. One of the legs is 2 inches longer than the other one. If x is the length of the shorter leg, what is the equation

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Answer:

The equation is

X²+2x-48 = 0

Shorter one is 6 inches

Other side= 8 inches

Explanation:

The equation for a right angle triangle normally is

A² = B² + C²

Where A = hypotenuse

Then B and C are the order sides of the triangle.

This time

Hypotenuse= 10 inches

The shorter one is X

While the other one is X+2

The equation

10²= x² +(x+2)²

100= x² + x² + 4x +4

100 - 4 = 2x² +4x

96= 2x² +4x

48 = x² +2x

X²+2x-48 = 0

Solving for x

X² +8x-6x-48= 0

X(x+8)-6(x+8)=0

(X-6)(x+8)= 0

X= 6 or x= -8

Definitely x is posiy

So x= 6

Shorter one is 6 inches

Other side= 6+2= 8 inches

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