Answer:
v_A = 6 m/s , v_B = 0 m/s , v_C = - 4 m/s , v_D = -4 m/s , v_E = 2.66 m / s
Step-by-step explanation:
For this exercise we use the definition of average velocity in each segment
v_average = (x₂-x₁) / Δt
segment A of the graph you take the value of distance and time
x₁ = 0 m t₁ = 0 s
x₂ = 60 m t₂ = 10 s
using the average velocity equation and calculate
v_A = (60-0) / (10-0)
v_A = 6 m / s
Segment B
x₁ = 60m
x₂ = 60 m
since the displacement variation is zero (particle stopped) the velocity is zero
v_B = 0 m / s
Segment C and D
x₁ = 60 m t1 = 15 s
x₂ = -40 m t2 = 40 s
v_C = (-40 -60) / (40 -15)
v_C = - 4 m / s
Segment D
how is the same line
v_D = -4 m / s
Segment E
x₁ = -40 m t₁ = 40 s
x₂ = 0 m t₂ = 55 s
v_E = (0- (-40)) / (55 -40)
v_E = 2.66 m / s