Question

(a) A standard sheet of paper measures 8 1/2 by 13 inches. Find the area of one such sheet of paper in m2.8.5(!meter/39.37in) — 0.2159 13 (!meter/39.37in ) — 0.3302 0.2159 X 0.3302 = 0.0713

= 0.0713 m2 (b) A second sheet of paper is three-quarters as long and three-quarters as wide as the one described in part (a). By what factor is its area less than the area found in part(a)?= _____________ times less

Answer 1

a) A = 0.07129 m²

b) A / A ’= 1.77

Step-by-step explanation:

In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

l = 0.3302 m

The area of ​​a rectangle is

A = l a

A = 0.3302 0.2159

A = 0.07129 m²

b) we have a second sheet with reduced dimensions

a ’= 3/4 a

l ’= ¾ l

Let's find the area of ​​this glossy sheet

A ’= l’ a ’

A ’= ¾ l ¾ a

A ’= 9/16 l a

To find the factor we divide the two quantities

A / A ’= l a 16 / (9 l a

A / A ’= 1.77