Answer:
9.2 s
Step-by-step explanation:
Using one of the equation of motion v = u + at where;
v is the final velocity = 0m/s (the ball comes to rest after throw)
u is the initial velocity = 46m/s
a is the acceleration = -5m/s² (the body decelerates)
t is the time taken by the ball in air
substituting the given parameters into the formula to get t, we will have;
0 = 46 +(-5)t
0 = 46 - 5t
subtract 46 from both sides
0-46 = 46-5t-46
-46 = -5t
Divide both sides by -5
-46/-5 = -5t/-5
t = 46/5
t = 9.2seconds
Hence it will take the ball 9.2seconds in the air before coming to rest.