Answer: 4
Explanation:
Let the consecutive integers be x, x+1 and x+2.
There are three consecutive integers such that twice the sum of the smallest and the largest is eight more than twice the largest. This means that:
2(x + x+2) = 2(x+2) + 8
2(2x + 2) = 2x + 4 + 8
4x + 4 = 2x + 12
Collect like terms
4x - 2x = 12 - 4
2x = 8
x = 8/2
x = 4
The smallest integer in the sequence is 4