Question

There are three consecutive integers such that twice the sum of the smallest and the largest is eight more than twice the largest. Find the smallest integer in the sequence.

Answer 1

Answer: 4

Explanation:

Let the consecutive integers be x, x+1 and x+2.

There are three consecutive integers such that twice the sum of the smallest and the largest is eight more than twice the largest. This means that:

2(x + x+2) = 2(x+2) + 8

2(2x + 2) = 2x + 4 + 8

4x + 4 = 2x + 12

Collect like terms

4x - 2x = 12 - 4

2x = 8

x = 8/2

x = 4

The smallest integer in the sequence is 4