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Given R = (-3,2) and D = (3,-3) find RD

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Answer:


\boxed{ \bold{ \huge{ \boxed{ \sf{ √(61) \: \: units}}}}}

Explanation:

Let R ( -3 , 2 ) be ( x₁ , y₁ ) and D ( 3 , -3 ) be ( x₂ , y₂ )

Using distance formula


\boxed{ \sf{distance = \sqrt{ {(x2 - x1)}^(2) + {(y2 - y1)}^(2) } }}


\dashrightarrow{ \sf{ \sqrt{ {(3 - ( -3)) }^(2) + {( - 3 - 2)}^(2) } }}


\dashrightarrow{ \sf{ \sqrt{ {(3 + 3)}^(2) + {( - 3 - 2)}^(2) } }}


\dashrightarrow{ \sf{ \sqrt{ {6}^(2) + {( - 5)}^(2) } }}


\dashrightarrow{ \sf{ √( 36 + 25 ) }}


\dashrightarrow{ \sf{ √(61) }} units

Hope I helped!

Best regards! :D

User Ladislav Mrnka
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