Question

Find the 10th term of a geometric sequence if a1=5 and the common ratio r=2

Answer 1

The 10th term of the GP is 2560.

Explanation:

It is given that,

The first term of the GP, a = 5

Common ratio, r = 2

We need to find the 10th term of the GP. The nth term of a GP is given by :

`T_n=ar^(n-1)`

Put n = 10

`T_(10)=5* 2^(10-1)\\\\T_(10)=2560`

So, the 10th term of the GP is 2560.