Answer:
x=3 and y=2
Explanation:
Let's solve your system by substitution.
4x−3y=6;7x+3y=27
Step: Solve4x−3y=6for x:
4x−3y=6
4x−3y+3y=6+3y(Add 3y to both sides)
4x=3y+6
4x /4 = 3y+6 /4 (Divide both sides by 4)
x= 3 /4 y+ 3 /2
Step: Substitute
3 /4 y+ 3 /2 for x in7x+3y=27:
7x+3y=27
7( 3 /4 y+ 3 /2 )+3y=27
33 /4 y+ 21 /2
=27 (Simplify both sides of the equation)
33 /4 y+ 21 /2 + (−21 /2 )
=27+ (−21 /2) (Add (-21)/2 to both sides)
33 /4 y= 33 2
33/4y=33/2
33 /4 =33/4 (Divide both sides by 33/4)
y=2
Step: Substitute 2 for y in x= 3 /4 y+ 3 /2
x= 3 /4 y+ 3 /2
x= 3 /4 (2)+ 3 /2
x=3 (Simplify both sides of the equation)
Answer:
x=3 and y=2
HOPE THIS HELPS!!!! :)
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