Answer:
A. 12 and 43
Explanation:
Pythagorean theorem is given as =
![a^2 + b^2 = c^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yenc9dfxchbh2erecctna2kggnymsvqrbi.png)
Where, a and b are the two legs of the right triangle, while c is the hypotenuse/longest leg of the triangle.
In the figure given, the side of the largest square = the hypotenuse of the triangle = c
While the side of the other squares = a and b respectively, of the triangle.
Area of square = s², where s is the side length of the square.
Since we are given that the area of the largest square = 55, this is also equivalent to c² in the Pythagorean theorem.
The side length of the largest square = √55 ≈ 7.4 = c
Therefore, to determine the area of the other squares, check the options given if they add up to give 55.
Option A: 12 + 43 = 55
Option B: 14 + 40 = 54
Option C : 16 + 37 = 53.
The correct possible areas of the smaller squares would be A. 12 and 43.