Question

3. Two fair dice are thrown once, find the probability of getting a total score greater than 5

Answer 1

13/18.

Explanation:

The favourable outcomes are (1,5) (1,6) (2,4) (2,5) (2,6) (3,3) (3,4) (3,5) (3,6) (4,2)(4,3) (4,4) 4,5) (4,6) 5,1) (5,2) 5,3) (5,4) (5,5) (5,6 )(6,1) to (6,6).

= total of 26.

As the total of all possible outcomes is 36 the answer is 26/36

= 13/18.

Answer 2

26/36

Explanation:

The probability of something = the amount of favourable outcomes/total possible outcomes.

The total number of dice combinations is 36 (6x6).

In this case there are more outcomes more than 5 than less than 5 so for the sake of simplicity we are going to find the number of outcomes less than 5 and then find the inverse.

There are only 10 possible dice combos which add to totals 5 or under:

1,1 1,2 2,1 1,3 3,1 1,4 4,1 2,2 2,3 and 3,2

That means there is a 10/36 probability of getting a total score less than 5 so to get the probability of getting more than 5, we just do 36/36 - 10/36 (because all probabilities add to 1)

Therefore there is a 26/36 probability that the toatals will add to greater than 5.

Alternatively you could also draw up a possibilities table and count the favourable outcomes.

Hope this helped!