Question

3 + root 3 *2 +root 2​

Answer 1

6 + 3
`√(2)` + 2
`√(3)` +
`√(6)`

Explanation:

Using the rule of radicals

`√(a)` ×
`√(b)` ⇔
`√(ab)`

Given

(3 +
`√(3)` )(2 +
`√(2)` )

Each term in the second factor is multiplied by each term in the first factor, that is

3(2 +
`√(2)` ) +
`√(3)` (2 +
`√(2)` ) ← distribute both parenthesis

= 6 + 3
`√(2)` + 2
`√(3)` +
`√(6)`