Question

Please help me
sec theta - cos theta= sin^2 theta/ cos theta​

Answer 1

Explanation:

Let theta be β.

So,

`sec\beta - cos\beta = (sin^2\beta )/(cos\beta ) \\=>(1)/(cos\beta ) - cos\beta = (1 - cos^2\beta )/(cos\beta ) \\=>(1 - cos^2)/(cos\beta ) = (1 - cos^2\beta )/(cos\beta )`

Here , identity used =
`sin^2\beta + cos^2\beta = 1`

Answer 2

Taking LHS

=1 by cos theta- cos theta

= (1- cos²0)/ cos0

= sin²0/ cos0 ( because 1-cos²0 is also equals to sin²0)

=RHS hence proved