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A sample of iron shot is added to a graduated cylinder containing 47.5 mL of water. The water level rises to the 51.1 mL mark. The density of iron is 7.87 g/mL. From this information, calculate the mass of the sample. *

1 Answer

5 votes

Answer:

The mass of iron shot is 28.3 grams.

Step-by-step explanation:

Given that the initial volume of water is 47.5 mL and final volume of water containing iron shot is 51.1mL. First, you have to find the volume of iron shot by subtracting :


47.5 + iron \: shot = 51.1


iron \: shot = 51.1 - 47.5


iron \: shot = 3.6ml

Next, we have to apply density formula, D = mass/volume :


d = (m)/(v)


let \: d = 7.87,v = 3.6


7.87 = (m)/(3.6)


m = 7.87 * 3.6


m = 28.3g \: (3sf)

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