Question

A graduated cylinder is filled with 3 mL of water. A toy car that

weighs 29 g is gently placed in the cylinder and the water level
rises to 19 mL. What is the density of the toy car? Round to the
thousandths place.

Answer 1

1.813 g/mL

Step-by-step explanation:

The density can be found with the following formula.

`d= (m)/(v)`

where
`m` is the mass and
`v` is the volume.

We know the mass is 29 grams. We must find the volume.

The volume is equal to the volume of water that is displaced. Subtract the initial volume of water from the final volume.

⇒ final volume - initial volume of water

The initial volume of water is 3 mL and the final volume is 19 mL.

⇒ 19 mL - 3 mL

⇒ 16 mL

The volume of the toy car is 16 mL.

Now we know the mass and the volume.

`m= 29g\\v=16mL`

Substitute the values into the formula.

`d=(m)/(v)`

`d=(29g)/(16mL)`

`d=1.8125 g/mL`

Round to the nearest thousandth. The 5 in the ten thousandth place tells us to round the 2 to a 3.

`d\approx1.813 g/mL`

The density of the toy car is about 1.813 grams per milliliter.

Answer 2

Density = 1.813 g/mL

Step-by-step explanation:

The density of a substance can be found by using the formula

`Density = (mass)/(volume)`

From the question

mass of toy car = 29 g

Volume = New volume - original volume of water in cylinder

That's

volume = 19 - 3 = 16 mL

Substitute the values into the above formula and solve for the density

That's

`Density = (29)/(16) \\ = 1.8125`

We have the final answer as

Density = 1.813 g/mL to the nearest thousandth

Hope this helps you