Question

What is the equation of a line that is perpendicular to y = -1/5x + 1 and passes through point (0, -2)?

Answer 1

y = 5x - 2

Explanation:

The slope will be 5, because that is the opposite reciprocal of the original slope, -1/5

Then, plug the slope and the given point into y = mx + b to find b:

y = mx + b

-2 = 5(0) + b

-2 = 0 + b

-2 = b

Then, plug the y-intercept and the slope into the equation:

y = 5x - 2 will be the equation