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Find the equation of a line containing the point (8.3) and has a slope of 5. Write

the equation in slope-intercept form

2 Answers

6 votes
Y=5x-37 and your all done
User Kymo Wang
by
8.7k points
1 vote

Answer:


y=5x-37

Explanation:

So we want to find the equation of a line with a slope of 5 and passes through (8,3).

To do so, we can use the point-slope form. This point-slope form is:


y-y_1=m(x-x_1)

Let's let (8,3) be x₁ and y₁ and let's let m equal 5. Therefore:


y-3=5(x-8)

Distribute the right:


y-3=5x-40

Add 3 to both sides:


y=5x-37

That would be our equation in slope-intercept form.

And we're done!

User Pshemo
by
8.5k points

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