Question

(-2ab^-5)(4a^-2b)^-2

Answer 1

-a^5/(8b^7)

Explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)^c = a^(bc)

a^-b = 1/a^b

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`(-2ab^(-5))(4a^(-2)b)^(-2)=(-2ab^(-5))(4^(-2)a^(-2(-2))b^(-2))\\\\=(-2)/(16)a^(1+4)b^(-5-2)=\boxed{-(a^5)/(8b^7)}`