Please show me how to solve this! Y^7Z^3/y^4z

asked Apr 27, 2021 201k views

1 vote

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5 votes

Answer:

(y^3)(z^2)

Explanation:

subtract the common based exponents

Greylander answered Apr 29, 2021

4.8k points

6 votes

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$\sf{(y^7z^3)/(y^4z)}\\\\=\tt{(y^7)/(y^4)×(z^3)/(z^1)}\\\\=\tt{y^((7-4))×z^((3-1))}\\\\=\tt{(y^3)×(z^2)}\\\\\pmb{\green{\boxed{\bold{y^3z^2}}}}$

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Kimsk answered May 1, 2021

by Kimsk

4.3k points

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