Question

Y+9÷2=y-3÷4-(y/3)
pls help​

Answer 1

y = -
`(63)/(4)` or - 15.75

Explanation:

Order of operations.

y +
`(9)/(2)` = y -
`(3)/(4)` -
`(y)/(3)` Subtract y from each side.

y - y +
`(9)/(2)` = y - y -
`(3)/(4)` -
`(y)/(3)`

`(9)/(2)` = -
`(3)/(4)` -
`(y)/(3)` Add
`(3)/(4)` to each side

`(9)/(2)` +
`(3)/(4)` = -
`(3)/(4)` +
`(3)/(4)` -
`(y)/(3)`

`(9)/(2)` +
`(3)/(4)` = -
`(y)/(3)` Find the common denominator for
`(9)/(2)` and
`(3)/(4)`, which is 4

`(9)/(2)` *
`(2)/(2)` +
`(3)/(4)` = -
`(y)/(3)`

`(18)/(4)` +
`(3)/(4)` = -
`(y)/(3)`

`(21)/(4)` = -
`(y)/(3)` Multiply each side by 3

`(21)/(4)` * 3 = -
`(y)/(3)` * 3

`(63)/(4)` = - y Divide each side by -1

y = -
`(63)/(4)` = - 15
`(3)/(4)`

y = - 15.75

Answer 2

Explanation:

There are 2 scenarios below. One without parenthesis and the second with. I believe the second one is your question.

• y+9÷2=y-3÷4-(y/3)
• y - y + y/3 = - 3/4 - 9/2 ⇒ combining like terms
• y/3 = -3/4 - 18/4
• y/3 = -21/4
• y = -21/4*3
• y = -63/4
• y = - 15 3/4

===============

• (y+9)÷2=(y-3)÷4-(y/3)
• 12*(y+9)/2 = 12* (y-3)/4 - 12*y/3 ⇒ this is to get rid of fraction
• 6(y+9) = 3(y-3) - 4y
• 6y + 54 = 3y - 9 - 4y
• 6y + 54 = - y - 9
• 6y + y = - 9 - 54
• 7y = - 63
• 7y/7 = -63/7
• y = -9