Question

Write an equation of a line in point-slope and slope intercept form that passes through the point (1, -8) and is perpendicular to the line: 2x-4y = -11

Answer 1

11y-2x= -90

Explanation:

for the point (1,-8)

x=1 and y= -8

for the equation,

2x -4y= -11

x= -1/m

m= -1/x

x = -1/ (-11/2 )

m= 2/11

so for the equation,

y-y1= m(x- x1)

y- -8=2/11(x-1)

11(y+8)= 2(x-1)

11y +88= 2x-2

11y-2x= -90